-2x^2+4x+6=10

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Solution for -2x^2+4x+6=10 equation: 



-2x^2+4x+6=10

We move all terms to the left:

-2x^2+4x+6-(10)=0

We add all the numbers together, and all the variables

-2x^2+4x-4=0

a = -2; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-2)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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